hm.tp M Homework & Chapter 6X mazon.com-Online Sh... value: 5.00 points Industry
ID: 3133106 • Letter: H
Question
hm.tp M Homework & Chapter 6X mazon.com-Online Sh... value: 5.00 points Industry standards suggest that 10 percent of new vehicles require waranty service within the fist year Jones Nissan in Sumter, South Carolina, sold 13 Nissans yesterday. (Round your mean answer to 2 decimal places and the other answers to 4 decimal places.) al places and the other answers to 4 decimal places.) a. What is the probability that none of these vehicles requires warranty service? b. What is the probability exactly one of these vehicles requires warranty service? Pr obability c. Determine the probability that exactly two of these vehicles require warranty service Probability Probability d. Compute the mean and standard deviation of this probability distribution. Mean Standard deviation References eBook & Resources WorksheetExplanation / Answer
probability to require warranty service = 0.10
probability not require waranty service = 0.90
a) p(x=0 require) = 13C0*(0.10)*(0.9)^13 = 0.254
B) P(X = ATLEAST 1) = 1 - P(X= 0)
= 1 - 0.254 = 0.746
C) P(X=2) = 13C2*(0.1)^2*(0.9)^11 = 0.979
D) MEAN = 13*0.1 = 1.3 WILL REQUIRE ON AVERAGE
VARIANCE = E(X^2) - E(X)^2 = 169*0.1 - (1.3*1.3)
= 15.21
STANDARD DEVIATION = SQRT(VARIANCE) = (15.21)^(1/2) = 3.9
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