A sample of 44 observations is selected from a normal population. The sample mea

Question

A sample of 44 observations is selected from a normal population. The sample mean is 24, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.05 significance level. H0: 23 H1: > 23 17. value: 10.00 points Required information a. Is this a one- or two-tailed test? One-tailed test Two-tailed test References eBook & Resources Multiple ChoiceDifficulty: 2 IntermediateLearning Objective: 10-05 Conduct a test of a hypothesis about a population mean. Check my work 18. value: 10.00 points Required information c. What is the value of the test statistic? (Round your answer to 2 decimal places.) Value of the test statistic References eBook & Resources WorksheetDifficulty: 2 IntermediateLearning Objective: 10-05 Conduct a test of a hypothesis about a population mean. Check my work 19. value: 10.00 points Required information d. What is your decision regarding H0? Reject H0 Fail to reject H0 References eBook & Resources Multiple ChoiceDifficulty: 2 IntermediateLearning Objective: 10-05 Conduct a test of a hypothesis about a population mean. Check my work 20. value: 10.00 points Required information e. What is the p-value? (Round your answer to 4 decimal places.) p-value

Explanation / Answer

17.

Formulating the null and alternative hypotheses,              
              
Ho:   u   <=   23  
Ha:    u   >   23  
              
As we can see, this is a    right   tailed test.

Hence, it is a ONE TAILED TEST.       [ANSWER]

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18.   

Getting the test statistic, as              
              
X = sample mean =    24          
uo = hypothesized mean =    23          
n = sample size =    44          
s = standard deviation =    3          
              
Thus, z = (X - uo) * sqrt(n) / s =    2.211083194   [ANSWER, TEST STATISTIC]

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19.
              
Thus, getting the critical z, as alpha =    0.05   ,      
alpha =    0.05          
zcrit =    +   1.644853627      
              
      
              
Also, the p value is              
              
p =    0.013515038          
              
As z > 1.645, and P < 0.05, we   REJECT THE NULL HYPOTHESIS.          

ANSWER: REJECT HO   

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20.

As this is one tailed, the p value is              
              
p =    0.013515038   [ANSWER]      

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