I will be thankfule to any one can help me to pass this EXAM. Give an example of

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I will be thankfule to any one can help me to pass this EXAM.

Give an example of type-I error 18. Given an example of type-II error 19. A particular depression scale has a mean of 20 in the population with a standard deviation of 4. A researcher at Eastern Michigan University wants to test the claim that the gloomy grey skies of Michigan winters cause elevations in depression compared to the rest of the population. She samples 80 Michiganders and measures depression levels in February using the depression scale noted above. She finds a sample mean equal to 27. For a two-tailed test with alpha =.05, answer the following: a. What is the null hypothesis? What is the alternative hypothesis? b. What are the critical z-scores used to determine statistical significance? c. What is the z-score for the sample mean? d. What do you conclude? e. What is the effect size? For a one-tailed test with alpha =.05, answer the following: a. What is the null hypothesis? What is the alternative hypothesis? b. What is the critical z-score used to determine statistical significance? c. What is the z- score for the sample mean? d. What do you conclude?

Explanation / Answer

Q19. TWO TAILED
Set Up Hypothesis
Null Hypothesis H0: U=20
Alternate Hypothesis H1: U!=20
Test Statistic
Population Mean(U)=20
Given That X(Mean)=27
Standard Deviation(S.D)=4
Number (n)=80
we use Test Statistic (Z) = x-U/(s.d/Sqrt(n))
Zo=27-20/(4/Sqrt(80)
Zo =15.6525
| Zo | =15.6525
Critical Value
The Value of |Z | at LOS 0.05% is 1.96
We got |Zo| =15.6525 & | Z | =1.96
Make Decision
Hence Value of | Zo | > | Z | and Here we Reject Ho
P-Value : Two Tailed ( double the one tail ) - Ha : ( P != 15.6525 ) = 0
Hence Value of P0.05 > 0, Here we Reject Ho

[ANS]
a. H0: U=20 H1: U!=20
b. LOS 0.05% is 1.96
c. Z score = 15.625
d. Here we Reject Ho

ONE TAILED

Set Up Hypothesis
Null H0: U<20
Alternate H1: U>20
Test Statistic
Population Mean(U)=20
Given That X(Mean)=27
Standard Deviation(S.D)=4
Number (n)=80
we use Test Statistic (Z) = x-U/(s.d/Sqrt(n))
Zo=27-20/(4/Sqrt(80)
Zo =15.6525
| Zo | =15.6525
Critical Value
The Value of |Z | at LOS 0.05% is 1.64
We got |Zo| =15.6525 & | Z | =1.64
Make Decision
Hence Value of | Zo | > | Z | and Here we Reject Ho
P-Value : Right Tail - Ha : ( P > 15.6525 ) = 0
Hence Value of P0.05 > 0, Here we Reject Ho

[ANS]
a. H0: U<20 H0: U>20
b. LOS 0.05% is 1.64
c. Z score = 15.625
d. Here we Reject Ho

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