Allied Corporation wants to increase the productivity of its line workers. Four

Question

Allied Corporation wants to increase the productivity of its line workers. Four different programs have been suggested to help increase productivity. Twenty employees, making up a sample, have been randomly assigned to one of the four programs and their output for a day's work has been recorded. You are given the results below. Program A Program B Program C Program D 150 150 185 175 130 120 220 150 120 135 190 120 180 160 180 130 145 110 175 175 State the null and alternative hypotheses. Construct an ANOVA table. As the statistical consultant to Allied, what would you advise them? Use a .05 level of significance. Use Fisher's LSD procedure and determine which population mean (if any) is different from the others. Let = .05.

Explanation / Answer

H0: All the four groups means are equal

H1: Atleat one group mean is not same

Alpha:5%

Test statistic:

From Excel

The Fcal =6.140

Conclusion: P value=0.0056 < 0.05 we reject the Null hypothesis.

Hence one of group mean is not same

Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 5 725 145 525 B 5 675 135 425 C 5 950 190 312.5 D 5 750 150 637.5 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 8750 3 2916.667 6.140351 0.00557 3.238872 Within Groups 7600 16 475 Total 16350 19

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