the average score of all golfers for a particular course has a mean of 80 and a

Question

the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81
the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81
the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81

Explanation / Answer

From information given, Xi=81, Xbar=80, s=5. Substitute the value sto obtain the z score.

z=(Xi-Xbar)/s=(81-80)/5=0.2

Look into z table and find area beyond z=0.2, this gives the required probability.

Ans: P(X>81)=0.4207.

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