The pedigree below shows the transmission of albinism (absence of skin pigment)

Question

The pedigree below shows the transmission of albinism (absence of skin pigment) in a human family.
Black color represents albinism and white color represents normal pigmentation.

- mode of transmission of albinism is autosomal recessive

- genotypes of males and females in generation 1 is Aa

The female I-1 and her mate, male I-2, had four children, one of whom has albinism. What is the probability that they could have had a total of four children with any other outcome except one child with albinism and three with normal pigmentation?

What is the probability that any of the other four children are carriers of the allele for albinism?

Explanation / Answer

a)

The probability of any outcome except one child with albinism and other 3 children with normal pigmentation would be 0 because, the trait is inherited as autosomal recessive and definitely one normal, two carriers and one affected children are resulted due to the trait following the monohybrid cross ratio.

b)

There would be 50% of chance for half of the children (2) for being carriers for the allele.

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