Use the accompanying table of standard scores and their percentiles under the no
ID: 3136244 • Letter: U
Question
Use the accompanying table of standard scores and their percentiles under the normal distribution to find the approximate standard score of the following data values. Then state the approximate number of standard deviation that the value lies above or below the mean. Use the accompanying table of standard scores and their percentiles under the normal distribution to find the approximate standard score of the following data values. Then state the approximate number of standard deviation that the value lies above or below the mean.a. A data value in the 40th percentile b. A data value in the 60th percentile c. A data value in the 54th percentile
Click the icon to view the table. a. The standard score for the 40th percentile is approximately (Round to two decimal places as needed.) The 40th percentile lies approximately standard deviations | (Round to two decimal places as needed.) | the mean b. The standard score for the 60th percentile is approximately (Round to two decimal places as needed.) The 60th percentile lies approximately standard deviations (Round to two decimal places as needed.) | the mean. c. The standard score for the 54th percentile is approximately (Round to two decimal places as needed.) The 54th percentile lies approximately standard deviations! (Round to two decimal places as needed.) | the mean
Explanation / Answer
From the given table:
a)
Standrad score (or z score) for 40th percentile is -0.25
The 40th percentile lies approximately 0.25 standard deviation below the mean.
b)
Standrad score (or z score) for 60th percentile is 0.25
The 60th percentile lies approximately 0.25 standard deviation above the mean.
c)
Standrad score (or z score) for 54th percentile is 0.10
The 60th percentile lies approximately 0.10 standard deviation above the mean.
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