Can someone help me with all the questions? I’m really struggling 2. Find all va
ID: 3136991 • Letter: C
Question
Can someone help me with all the questions? I’m really struggling 2. Find all values of c such that the matrix is NOT invertible. c+4 -1 c+5 -3 3 Lc+6-3 +7 3. Describe the additive identity and additive inverse of the vector space M2s 4. Let A be the standard matrix of a linear transformation T:-. If the range of T has dimension 2, determine the dimension of each of the following subspaces: a) Col A b) Null A c) Row A 5. Determine if the given set is a subspace of : 144 6. Find the basis for a) the null space of A, b) the column space of A, c) the row space of A. 1 2 -1 1 4 -5 7. Find a basis for and the dimension of the solution space of Ax-0 2x, +4x2 3x,-6x, -0 3x, +6x+5x,-11x,-0 a) Prove that ß is a basis for R' b) Find vif [v],# 1-3 c) Find [w), if w[-2Explanation / Answer
2. Let A =
c+4
-1
c+5
-3
3
-4
c+6
-3
c+7
Then det(A) = -2c -6 = 0 if c = 3. Thus A is not invertible if c = 3.
3. The additive identity of M2x5 is the 2x5 zero matrix, with all its entries equal to 0. The additive inverse of a 2x5 matrix A, whose ijth entry is aij, is the 2x5 matrix –A, whose ijth entry is -aij.
4. The standard matrix A of T: R5 R7 is a 7x5 matrix.
a). Range (T) is same as col(A). Hence dim(col(A)) = 2
b). As per the rank-nullity theorem, dim(null(A)) = 5-2 = 3.
c). dim(Row (A)) =- dim(col(A)) = 2.
5. Let X =(u1, u2,u3,u4)T and Y = (v1, v2,v3,v4)T are 2 arbitrary vectors in S, then X+Y = (u1+v1,u2+v2,u3+v3,u4+v4). Further, u2 = 0, v2 = 0, u4= 0 and v4= 0. Hence X+Y = (u1+v1,0, u3+v3,0)T. However, (u1+v1)2 = u12 +v12 + 2u1 v1 = u33 + v33 +2u1 v1 (u1+v1)3. Hence X+Y S so that S is not closed under vector addition. Hence S is not a subspace of R4.
Please post the remaining questions again, maximum of 4 at a time.
c+4
-1
c+5
-3
3
-4
c+6
-3
c+7
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