One player throws a baseball to another player standing 80ft away with initial s

Question

One player throws a baseball to another player standing 80ft away with initial speed 60ft/s. Find two angles theta at which the ball can be released so that the other player can catch the ball (assume y=0). Which angle gets the ball there faster? This is a calculus question and I am not allowed to use physics equation so solve it. Thanks.

Explanation / Answer

vsin(Theta) = 32.174t =>t = vsin(Theta)/32.174 = 60sin(theta)/32.174 40 = vcos(Theta)*60sin(theta)/32.174 = (60^2)sin(2*Theta)/(2*32.174) =>sin(2*Theta) = 0.714977778 =>2*Theta = 45.641378, 180-45.641378 =>Theta = 22.820689, 67.179311 t for angle of 67.179311 > t for angle 22.820689 So the angle 22.820689 gets the ball faster.

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