Name Prize Painting la Carmen enters a painting in an art contest The contest ru

Question

Name Prize Painting la Carmen enters a painting in an art contest The contest rules say all paintings must be rectangular, with an area no greater than gth the painting can have and still have an arca within the contest that 3,003.04 len rules? (Hin ength cm*. Carmen's painting is 16 cm wide. What is the greatest t: A rectangle's area is the product of the width and the Carmen, painting is i 6 crn u, ‘ de width x length (3C03, o42 l(o length-3003.0+ widde Length = 3003 04/1G)= ì8.lo9cm Carmen's painting wins second prize in the contest. The painting that wins first prize has an area that is 3.2 times smaller than the greatest area the rules allow. What is the area of the first-prize painting? Show your work. 5-27 Chapter Resources O Haughton Mma Harcourt Pusas hing Company Chapter 5 Performan

Explanation / Answer

a)

length = Area/width =3003.04/16 = 187.69cm

b) area = 3003.04/3.2 = 938.45

c) let the number of tubes of paint which can be bought =x

here

4.8*x + 2*6.7 = 35

x = 4.5

hence x = 4

d) width = 8137.68/82.7 = 98.4

since 98.4 > 95

the painting won't fit in the frame

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