Hw03 1.2: Problem 7 Previous Problem List Next (1 point) The length of the recta

Question

Hw03 1.2: Problem 7 Previous Problem List Next (1 point) The length of the rectangular tennis court at Wimbledon is 4 feet longer than twice the width. If the court's perimeter is 248 feet, what are the court's dimensions? The length is The width is thelpentering answers! See a similar example(PDF) feet feet Note: You can earn partial credit on this problem Preview My Answers Submit Answers Show me another You have attempted this problem 0 times You have 12 attempts remaining Page generated at 09/04/2017 at 05:11pm EDT WeBWorK 1996-2016 : theme, math41 vnv-version: 2.11 l pg-version 2 11: The weBworK Project 0

Explanation / Answer

Let the length be l and width be w.

Given l = 4 + 2w feet

=> l - 2w = 4 (1)

Perimeter :

2l+2w = 248 (2)

Adding (1) and (2)

=> 3l = 252

=> l = 252/3 = 84 feet

Substituting in (1)

=> 84 - 2w = 4

=> 2w = 80

=> w = 80/2 = 40 feet

The length of the court is 84 feet

The breadth of the court is 40 feet.

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.