Consider a hide and seek game that encompasses two periods. There are three cell

ID: 3144159 • Letter: C

Question

Consider a hide and seek game that encompasses two periods. There are

three cells labeled 1, 2, 3. In the rst period the hider can hide in either cell 1 or 2 (but not 3).

In second period the hider can hide in any of the three cells. The seeker will detect the hider

if they both occupy the same cell in the same period. The seeker wins the game if he detects

the hider in either period. The hider wins if the seeker fails to detect him in either period.

Formulate and solve this game.

Alter the game so that the hider cannot move from cell 1 in period 1 to cell

3 in period 2 (this restricts the hider's speed). What is the probability that the seeker chooses

cell 2 in the first period now?

prob. Of hider wins=2/5*2/3+3/5*2/3=2/3.

(As first period have 6 cases while second have 9 cases so total 15 cases.out of which first have 4 and second have 6 case favourable to hider.)

Prob of seaker wins=1-2/3=1/3 .

In next condition there is no restrictions put on seaker choice so it choose cell 2 with prob =1/3.

(Problem is not clearly explain the condition so plz write problem statement clearly.)

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