I need help in this question it is necessary please This is in statistics Fall,

Question

I need help in this question it is necessary please This is in statistics Fall, 2017 terms. For all problems show your work, and state your conclusions in non-statistical I. The following data are from a study of the number of sexist words in male group conversations after having been either given or not given gender sensitivity training. Groups Without Training Groups With Training 10 a. State the null hypothesis and the alternative hypothesis. b. Calculate t and compare it with the t critical at the .05 level. What are your conclusions? Report on the effect size using eta-squared. Construct a confidence interval for the true mean difference. 2. A study was done looking at the number of pounds participants lost after six months of a weight loss program. Program A was diet only, Program B was diet and exercise, and Program C was exercise only. The dependent variable was the number of pounds lost.

Explanation / Answer

Question 1

Null Hypothesis : H0 : There is no difference in sexist words used in male group conversations when trained in gender sensitivity or not.

ALternative Hypothesis : Ha : There is significant reduction in use of sexist words in male group conversations when trained in gender sensitivity as compared tto untrained in gender sensitivity.

Let say group without training is 1 and group with training is 2

so sample mean of group 1 (x1 ) = 9.4

standard deviation of the sample s1 = 1.14

sample mean of group 2 (x2 ) = 5

standard deviation of the sample s2 = 1.87

Pooled standard deviation sp = sqrt [s12 + s22] /2 = sqrt [(1.142 + 1.872 )/2/ = 1.5486

Test statistic

t = (x1 - x2 )/ sp * sqrt(1/n1 + 1/n2 )

t = (9.4 - 5)/ 1.5486 * sqrt (1/5 + 1/5)

t = 4.49

as the test is one sided

tcritical = t0.05,8 = 1.859

so we can see that t > tcritc so we shall reject the null hypothesis and can conclude that There is significant reduction in use of sexist words in male group conversations when trained in gender sensitivity as compared tto untrained in gender sensitivity.

Effect size Eta -squared = SSTreatment/SStotal = 48.4/ 67.6 = 0.716

so effect size is pretty large here as sample sizes are pretty small.

Confidence interval for true mean difference

= (x1 - x2 ) +- t0.05,8  sp * sqrt [1/n1 + 1/n2]

= (9.4 -5) +- 1.859 * 1.5486 * sqrt (2/5)

= 4.4 +- 1.822

= (2.578, 6.222)

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