3. Solve each of the following equations a. log (3x +2) 2 1-3x c. 3114.3-7 = -1

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Dear Student Thank you for using Chegg !! a) log (3x + 2) = 2 => 3x + 2 = e^2 Since log(base a) (b) = P => b = a^P 3x + 2 = 7.38906 3x = 5.38906 x = 1.79635 b) e^ (1-3x) = 2 Taking natural log both sides 1- 3x = ln(2) 1- 3x = 0.69315 3x = 0.30685 x = 0.10228 c) 3.11^(4x + 3) - 7 = -1 3.11^(4x + 3) = 6 11^(4x + 3) = 2 Taking log(10) both sides we get (4x + 3) log10(11) = 0.30103 (4x+3) = 0.28906 4x = -2.71094 x = -0.67773 d) 10^(2x-1) = 515 Taking log(base10) both sides (2x-1) log10(10) = log10(515) (2x-1) = 2.71181 2x = 3.71181 x = 1.8559 Soution

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