With the parents of cross \"Bb x bb\", what is the probability of that 2 childre

Question

With the parents of cross "Bb x bb", what is the probability of that 2 children will have brown eyes and 2 children will have blue eyes (any order)? brown eyes(B) = dominant, blue eyes (b) = recessive
With the parents of cross "Bb x bb", what is the probability of that 2 children will have brown eyes and 2 children will have blue eyes (any order)? brown eyes(B) = dominant, blue eyes (b) = recessive
With the parents of cross "Bb x bb", what is the probability of that 2 children will have brown eyes and 2 children will have blue eyes (any order)? brown eyes(B) = dominant, blue eyes (b) = recessive

Explanation / Answer

Parents: Bb X bb

Gametes: B, b, b, b

F1 : Bb, Bb, bb, bb

1----------1 1----------1

Brown Blue

Probability that the children has brown eyes = 2 / 4 = 1/2 = 0.5 = 50%

Probality that the children has blue eyes = 2 / 4 = 1/2 = 0.5 = 50%

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