Referring back to the previous problem in which a researcher plans to test the t

Question

Referring back to the previous problem in which a researcher plans to test the theory the average cholesterol level of all men on a modified diet is less than 241. A study is planned in which a random sample of 12 patients who agree to participate in the study will follow the modified diet for 3 months. Unknown to the researcher, the real true average cholesterol level of ALL males aged 50 who follow the diet for 3 months is 235. The power for the experiment described above is 0.35. When the significance level is .05, what does a power = 0.35 mean?

a.35% of all samples of 12 men will lead the researcher to the decision to fail to reject the null hypothesis.

b.65% of all samples of 12 men will result in the conclusion that there is statistical evidence the average cholesterol level of all men on the modified diet is 242.    

c.65% of all samples of 12 men will lead the researcher to make a Type II error.

d.35% of all samples of 12 men will lead the researcher to make a Type I error.

e.Exactly 2 of the above.

Explanation / Answer

The power of an experiment is the probability of avoiding a Type II error [incorrectly failing to reject Ho.]

Hence,

P(type II) = 1 - Power) = 1 - 0.35 = 0.65 [So option C is correct]

All the other options are not correct. Hence,

OPTION C: c.65% of all samples of 12 men will lead the researcher to make a Type II error. [ANSWER]

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