I JUST NEED QUESTION 6! CAN YOU PLEASE DO OUT THE EXCEL FOR ME! HERE IS #5 WORK
ID: 3150519 • Letter: I
Question
I JUST NEED QUESTION 6!
CAN YOU PLEASE DO OUT THE EXCEL FOR ME!
HERE IS #5 WORK
1.Do exercise 8.131 on page 360 in the textbook
a.Obtain and interpret a 95% confidence interval for the additional sleep that would be obtained on average for all people using laevohysocyamine hydrobromide
Sample mean=xbar=(1.9+0.8+1.1+0.1+-0.1+4.4+5.5+1.6+4.6+3.4)/10 =23.3/10=2.33
sample variance=s^2=((1.9=2.33)^2 +(0.8-2.33)^2 +…+(3.4-2.33)^2))/10-1
((-0.43)^2+(-1.53)^2+…+(1.07)^2)/9
=36.081/9=4.009
sample standard deviation =s=s2=4.0090=2.0022492.0022
standard error (SE)=s/=0.6332
a=1-0.95=0.05
t(a/2,n-1)=2.2622
margin or error (ME)= t(a/2,n-1) xSE=1.4324
95% confidence interval is given by: xbar + & - =2.33 +&- 1.4324= (0.8976,3.7624)
95% CI is (0.8976, 3.7624)
interpretation: we are 95% confident that this confidence interval contains the true mean
b.Was the drug effective in increasing sleep?Explain your answer.
Yes the drug was effective since 0 is not in this interval
Explanation / Answer
Excel data analysis used
Column1
Mean
2.33
Standard Error
0.633166645
Median
1.75
Mode
#N/A
Standard Deviation
2.002248736
Sample Variance
4.009
Kurtosis
-1.421167166
Skewness
0.385805508
Range
5.6
Minimum
-0.1
Maximum
5.5
Sum
23.3
Count
10
Confidence Level(99.0%)
2.057687466
Lower limit
0.2723
Upper limit
4.3877
Column1
Mean
2.33
Standard Error
0.633166645
Median
1.75
Mode
#N/A
Standard Deviation
2.002248736
Sample Variance
4.009
Kurtosis
-1.421167166
Skewness
0.385805508
Range
5.6
Minimum
-0.1
Maximum
5.5
Sum
23.3
Count
10
Confidence Level(99.0%)
2.057687466
Lower limit
0.2723
Upper limit
4.3877
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