Provide a 95% confidence interval estimate of the mean number of detects per car

Question

Provide a 95% confidence interval estimate of the mean number of detects per car for the population of cars produced by this manufacturer (based on problem #3) 0 34510 1954 0.116 to 1958 0.658 to 2 345 0.786 to 1 797 The number of hours Americans sleep each night varies considerably with 12% of the population sleeping less than six hours to 3% sleeping more than eight hours (the Macmillan Visual Almanac, 1996). A sample of 25 individuals reported the hours of sleep per night as shown below. Assuming that the population has a normal distribution, develop a 95% confidence interval for the population mean number of hours of sleep each night? 6.54 to 7.18 6.89 to 8.24 6.4910 8.12 6.22 to 7.18 Bcause of the high production-changeover time and costs, a direction of manufacturing must convince management that a proposed manufacturing method rduces cost. The current production method operates with a mean cost of $220 per hour. A research study is to be conducted in which the cost of the new method will be measured over a sample production period Develop the null and alternative hypotheses that are most appropriate for this study H_0: mu greaterthanorequalto 220, H_a: mu 220 H_0: mu = 220, H_a: mu notequal 220 H_0: mu > 220, H_a: mu lessthanorequalto 220 Comment on the conclusion when H_0 cannot be rejected. New method reduce cost. New method does not reduce cost. The current method reduce cost The current method do not reduce cost.

Explanation / Answer

Here problem 4 says use problem 3, which is not available and 6 & 7 are already done. So i will do problem 5 only. Hope that is what is to be done

5. Here mean is 6.86 and sd is 0.78

Now z value for 95% CI is 1.96

Hence 95% CI is 6.86+/-1.96*0.78/sqrt(25)=6.86+/-0.306=6.54 to 7.18 hence answer is a.

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