P(0)= 0.00107374 = 0.00 1 P(1)= 0.01369021 =0.014 P(2)= 0.07272923 =0.073 P(3)=

Question

P(0)= 0.00107374 = 0.00 1

P(1)= 0.01369021 =0.014

P(2)= 0.07272923 =0.073

P(3)= 0.20606616 =0.206

P(4)= 0.32841794 =0.328

P(5)= 0.27915525 =0.279

P(6)= 0.09886748 =0.099

4. What is the probability that no more than 3 families say that their children have an influence on their vacation destinations? Explain and show how you get your answer.

5. Find the mean, variance, and standard deviation of this binomial distribution. Explain and show all steps to get your answers.

(Bonus Question - 10 points): You can receive 10% extra credit on this assignment if you verify by hand the binomial probabilities that StatCrunch computed in Problem #1. You may use the formula on page 203 and Example 3 on page 204 as a guide on how to calculate binomial probabilities by hand. Explain and show all steps to get your answers.

Explanation / Answer

4)

P( x < 3 ) = 0.001 + 0.014 + 0.073 + 0.206 = 0.294

MEAN = 0.001 * 0 + 0.014 * 1 + 0.073*2 + 0.206*3 + 0.328*4 + 0.279*5 + 0.099*6

MEAN = 4.079

VAR = 0.001 * 0 ^2+ 0.014 * 1^2 + 0.073* 2^2 + 0.206*3^2 + 0.328*4^2 + 0.279*5^2 + 0.099*6^2

VAR = 0.014 + 0.292 + 1.854 + 5.248 + 6.975 + 3.564

VAR = 17.947 - 4.079^2 = 1.308759

SD = SQRT ( 1.308759 ) = 1.144

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.