The items below (# 1.6 - 1.8) are based on the following scenario. A counseling

Question

The items below (# 1.6 - 1.8) are based on the following scenario. A counseling psychologist developing a technique to reduce procrastination has students time their procrastination for a week and uses this as a pretest measure of procrastination. Students then attend a workshop in which they are instructed to do a specific warm-up exerdse for studying by focusing on a pleasant activity. Students again time their procrastination for a week, and the time from this second week is the posttest measure. If the psychologist wants to see if there is a change (increase or decrease) in procrastination by students who attended his workshop, the appropriate description of "Population 2" (the comparison population) would be people whose posttest scores will be lower than their pretest scores. difference scores will be 0 or greater than 0. difference scores will be 0. difference scores will be smaller than their pretest scores. if the psychologist wants to see if there is a change (increase or decrease) in procrastination by 10 of the students who attended his workshop using the.05 significance level, the cutoff t score(s) would be -.62,0,+2.62 +2.262 -2.262,0 -2.262, +2.262 If the psychologist finds that the sum of squared deviations from the mean of the difference scores of the sample is 135, the estimated population variance would be 135/10 = 13.5 135/9 = 15.0 10/135 =.074 9/135 =.067

Explanation / Answer

A) difference score will be zero (option c)

b) cutoff (-2.262,2.262)

c) 135/9=15

as the sample variance(divisor n-1) unbiased estimator of population variance

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