To test the efficacy of a new cholesterol-lowering medication, 10 people are sel
ID: 3152455 • Letter: T
Question
To test the efficacy of a new cholesterol-lowering medication, 10 people are selected at random. Each has their LDL levels measured (shown below as Before), then take the medicine for 10 weeks, and then has their LDL levels measured again (After).
Give a 96.4% confidence interval for ?B??A, the difference between LDL levels before and after taking the medication. Assume the population is normal.
Confidence Interval =
please find the confidence interval thanks!
Subject Before After 192 194 128 91 143 110 187 154 178 161 195 198 183 181 179 188 112 122 127 135 4 10Explanation / Answer
Before
After
difference
192
194
-2
128
91
37
143
110
33
187
154
33
178
161
17
195
198
-3
183
181
2
179
188
-9
112
122
-10
127
135
-8
Descriptive statistics
difference
n
10
mean
9.0000
sample standard deviation
19.1137
t value with 9 df at 96.4% level =2.463
margin of error = t*se = 2.463*19.1137/sqrt(10) =14.8871
lower interval = mean –margin of error = 9-14.8871 = -5.8871
Upper interval = mean +margin of error = 9+14.8871 = 23.8871
Give a 96.4% confidence interval for BA, the difference between LDL levels before and after taking the medication. Assume the population is normal.
Confidence Interval = (-5.89, 23.89) ( two decimals)
Before
After
difference
192
194
-2
128
91
37
143
110
33
187
154
33
178
161
17
195
198
-3
183
181
2
179
188
-9
112
122
-10
127
135
-8
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