The Downtown Parking Authority of Tampa, Florida, reported the following informa
ID: 3152565 • Letter: T
Question
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 225 customers on the number of hours cars are parked and the amount they are charged. Number of Hours Frequency Amount Charged 1 19 $ 3 2 37 5 3 43 12 4 44 15 5 37 19 6 11 23 7 4 28 8 30 31 225 a. Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 decimal places.) Hours Probability 1 0.084 2 0.164 3 0.191 4 0.195 5 0.164 6 0.048 7 0.017 8 0.133 a-2. Is this a discrete or a continuous probability distribution? Continuous Discrete b-1. Find the mean and the standard deviation of the number of hours parked. (Do not round intermediate calculations. Round your final answers to 3 decimal places.) Mean 4.056 Standard deviation 2.09 b-2. How long is a typical customer parked? (Do not round intermediate calculations. Round your final answers to 3 decimal places.) The typical customer is parked for 4.056 hours c. Find the mean and the standard deviation of the amount charged. (Do not round intermediate calculations. Round your final answers to 3 decimal places.) Mean 17.000 Standard deviation 9.526
Explanation / Answer
a) Probability can be calculated by dividing each frequency by total of all frequencies (225).
The probability distribution is shown below:
b) consider the following table:
The mean is: mean = xP(x)=4.073
The Standard deviation is: SD=sqrt[x²P(x) - ([xP(x))²] = Sqrt[20.853-1.073²] = 2.061
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c) consider the following table:
The mean is: mean = xP(x)=$15.174
The Standard deviation is: SD=sqrt[x²P(x) - ([xP(x))²] = Sqrt[303.51-15.174²] = $8.546
Number of Hours Frequency Amount charged 1 19 3 2 37 5 3 43 12 4 44 15 5 37 19 6 11 23 7 4 28 8 30 31 SUM 225Related Questions
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