1. Assume Mike Trout has the following distribution of outcomes for 2012. If he
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Question
1. Assume Mike Trout has the following distribution of outcomes for 2012. If he gets hurt, he will need some time to recover even while in the lineup, so he cannot produce at his highest level even if he comes back from an injury. If he does not get hurt, then he is certain to either Produce A, B or C, with A > B > C.
Outcome
Probability
Return/Production
Gets Hurt, Misses Whole Season
10%
0 wins
Gets Hurt, Misses 1/2 season, Produces B
20%
1.5 wins
Gets Hurt, Misses 1/2 season, Produces C
10%
0.75 wins
Gets Hurt, Misses 1/4 season, Produces B
10%
3 wins
Gets Hurt, Misses 1/4 season, Produces C
10%
1.5 wins
No Injury, Produces A
20%
10 wins
No Injury, Produces B
10%
6 wins
No Injury, Produces C
10%
3 wins
Outcome
Probability
Return/Production
Gets Hurt, Misses Whole Season
10%
0 wins
Gets Hurt, Misses 1/2 season, Produces B
20%
1.5 wins
Gets Hurt, Misses 1/2 season, Produces C
10%
0.75 wins
Gets Hurt, Misses 1/4 season, Produces B
10%
3 wins
Gets Hurt, Misses 1/4 season, Produces C
10%
1.5 wins
No Injury, Produces A
20%
10 wins
No Injury, Produces B
10%
6 wins
No Injury, Produces C
10%
3 wins
Explanation / Answer
Ok, we have this table
The probability of A: 30%
The probability of B: 40%
The probability of C: 30%
Outcome Probability Return/Production Gets Hurt, Misses Whole Season 10% 0 Gets Hurt, Misses 1/2 season, Produces B 20% 1.5 Gets Hurt, Misses 1/2 season, Produces C 10% 0.75 Gets Hurt, Misses 1/4 season, Produces B 10% 3 Gets Hurt, Misses 1/4 season, Produces C 10% 1.5 No Injury, Produces A 20% 10 No Injury, Produces B 10% 6 No Injury, Produces C 10% 3Related Questions
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