This is what I have so far. Where do I go from here? Question 1 Ste atachment fe

Question

This is what I have so far. Where do I go from here? Question 1 Ste atachment fer sork A nutritionist is interested in the eating habits of college students. She asks a random sample of college determine if there is a difference between the proportion of male students and female students who Question 1 Sec aHachment students whether they prepared a home-cooked meal at least oncein the past week. She would like to al at least once in the past week. She would like to prepared a home cooked meal in the past week. a) State the null and b) 50 males and 50 females were randomly sampled. 12 males and 21 femal stated they prepared a home cooked meal in the past week. State the statistic and value of the statistic for the difference in proportions for this experiment. Use the Randomization distribution below to answer the next two parts of this question. The proportion of values at or below -0.180 and the proportion of values at or above 0.14 are each 0.047. 100 0.047 0.906 0.047 s0 0.30 0.25 0.200.15 0.10 0.050 0.05 0.10 .15 0.20 25 0.140 -0.180 c) Please state the p-value for this experiment: d) Using a significance level of =0.05, please state the conclusion of the experiment (circle one) 1. Reject Ho. The results are not statistically significant. We have insufficient evidence to conclude anything Do not reject Ho. The results are not statistically significant. We have insufficient evidence to conclude anything. 2. 3. Reject He The results are statistically significant. There is evidence of a difference between genders 4. Do not reject Ho. The results are statistically significant. There is evidence of a difference between genders. Page 2

Explanation / Answer

Null Hypothesis, There Is No Significance between them Ho: p1 = p2
Alternate Hypothesis, There Is Significance between them H1: p1 != p2
Test Statistic
Sample 1 : X1 =12, n1 =50, P1= X1/n1=0.24
Sample 2 : X2 =21, n2 =50, P2= X2/n2=0.42
Finding a P^ value For Proportion P^=(X1 + X2 ) / (n1+n2)
P^=0.33
Q^ Value For Proportion= 1-P^=0.67
we use Test Statistic (Z) = (P1-P2)/(P^Q^(1/n1+1/n2))
Zo =(0.24-0.42)/Sqrt((0.33*0.67(1/50+1/50))
Zo =-1.914
| Zo | =1.914
Critical Value
The Value of |Z | at LOS 0.05% is 1.96
We got |Zo| =1.914 & | Z | =1.96
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value: Two Tailed ( double the one tail ) -Ha : ( P != -1.914 ) = 0.0556
Hence Value of P0.05 < 0.0556,Here We Do not Reject Ho

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