The average amount you spend on a lunch during the week is not known. Based on p

Question

The average amount you spend on a lunch during the week is not known. Based on past experience, you are willing to assume that the standard deviation is about $ 2.40. You take a random sample of 36 lunches, and apply the central limit theorem. Round your answer to decimal places. Fill in the blank: According to the 68-95-99.7 rule about 95% of all samples will capture the mean of all of the invoices in the interval x plus or minus $ You perform 1000 significance tests using alpha = 0.05. Assuming that all null hypotheses are true, about how many of the test results would you expect to be statistically significant? Fill in the blank (Give your answer as an integer): I expect tests to be statistically significant. Computes in some One of these is the fuel efficiency or gas mileage, usually expressed as

Explanation / Answer

6.According to the 68-95-99.7 rule, 95% of all samples will capture x bar+/-2*standard deviations.

Thus the required answer is 2*2.40=4.8

7.If the experiments is repeated 1000 times then I expect 1000 tests to be statistically significant.

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