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A marketing manager for a chain of brake shops was considering two different ser

ID: 3154060 • Letter: A

Question

A marketing manager for a chain of brake shops was considering two different services for an in-store promotion: a wheel alignment or an oil change. She wanted to know if there was different demand for these services, before deciding which promotion to run nationally. She test marketed the wheel alignment promotion in ten shops in Cleveland, and the oil change promotion in ten shops in Detroit. She recorded the following sales of the two promotions:

SHOP NO.            WHEEL ALIGNMENT IN CLEVELAND         OIL CHANGE IN DETROIT

1   318                                                                 314

2   322                                                                 315

3   333                                                                 350

4 315                                                                 305

5   385                                                                 299

6   310                                                                 309

7   312                                                                 312

8   300 301

9   302 295

10 310                                                                 279

Part 1--State the null and alternate hypotheses in plain English sentences (not equations).

Part 2--Using Excel or any statistical package you are familiar with, do a direct comparison of two means to determine if there is a significant difference between the sales of the two services. Print out the computer results.

Part 3--Can you reject the null hypothesis? Why or why not?

Explanation / Answer

Null hypothesis is that two means are equal

Alternate hypothesis is that there is significant difference between the two means.

The mean of Group One minus Group Two equals -10.80
  95% confidence interval of this difference: From -31.41 to 9.81


  t = 1.1009
  df = 18
  standard error of difference = 9.810

The two-tailed P value equals 0.2854
  By conventional criteria, this difference is considered to be not statistically significant

We cannot reject null hypothesis as p value is greater than 0.05

Group   Group One     Group Two   Mean 308.90 319.70 SD 18.40 24.98 SEM 5.82 7.90 N 10     10    
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