Sickle-cell trait is a hereditary condition and can cause medical problems. Some
ID: 3154356 • Letter: S
Question
Sickle-cell trait is a hereditary condition and can cause medical problems. Some biologists suggest that sickle-cell trait protects against malaria. A study in Africa tested 529 children for the sickle-cell trait. There were 131 children with the sickle-cell trait, and 38 of these had heavy malaria infections. There were 398 children without the sickle-cell trait, and 155 of these had heavy malaria infections.
Sickle-cell trait is a hereditary condition and can cause medical problems. Some biologists suggest that sickle-cell trait protects against malaria. A study in Africa tested 529 children for the sickle-cell trait. There were 131 children with the sickle-cell trait, and 38 of these had heavy malaria infections. There were 398 children without the sickle-cell trait, and 155 of these had heavy malaria infections The estimated difference in proportions of heavy malaria infections in children with and without the sickle cell trait is closest to 0.365 0.389 0.099 0.29 Submit Answer Tries 0/1 Is there good evidence that the proportion of heavy malaria infections in children with the sickle cell trait (p1) is lower than the proportion of heavy malaria infections in children without the sickle cell trait (P2)? The alternative hypothesis is HA: p1p2 HA: P1 P2 Submit Answer Tries 0/1 Is there good evidence that the proportion of heavy malaria infections in children with the sickle cell trait is lower than the proportion of heavy malaria infections in children without the sickle cell trait? The standard error for the test statistic is closest to 0.048 0.040 0.058 0.021 0.024 Submit Answer Tries 0/1 Is there good evidence that the proportion of heavy malaria infections in children with the sickle cell trait is lower than the proportion of heavy malaria infections in children without the sickle cell trait? The p value for this hypothesis test is closest to 0.365 0.0400 0.0200 0.389 0.290 Submit Answer Tries 0/1Explanation / Answer
1) p1-p2=38/131-155/398=-0.099
2) HA:p1<p2
3) SE(p1-p2)=sqrt [p1q1/n1+p2q2/n2]
=sqrt [(0.29*0.71)/131+(0.39*0.61)/398]
=0.048
4) Z=(p1-p2)-0/SE(p1-p2)
=-0.099-0/0.048
=-2.06
p value is 0.0200
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.