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For each of the following situations give the degrees of freedom and an appropri

ID: 3154513 • Letter: F

Question

For each of the following situations give the degrees of freedom and an appropriate bound on the P-value (give the exact value if you have software available) for the 2 statistic for testing the null hypothesis of no association between the row and column variables.

(a) A 2 by 2 table with 2 = 0.99.

df =

P-value =

(b) A 4 by 4 table with 2 = 17.53.

df =

P-value =

(c) A 2 by 8 table with 2 = 22.7.

df =

P-value =

(d) A 5 by 3 table with 2 = 13.2.

df =

P-value =

Please show work confused on how to solve....

Explanation / Answer

(a)df=(row-1)*(column-1)=(2-1)*(2-1)=1

Using a P Value from Chi-square Calculator, The P-Value is 0.319742. The result is not significant at p < 0.05.

(b)df=(4-1)*(4-1)=9

Using a P Value from Chi-square Calculator, The P-Value is 0.041035. The result is significant at p < 0.05.

(c)df=(2-1)*(8-1)=7

Using a P Value from Chi-square Calculator, The P-Value is 0.001922. The result is significant at p < 0.05.

(e)df=(5-1)*(3-1)=8

Using a P Value from Chi-square Calculator, The P-Value is 0.105151. The result is not significant at p < 0.05.

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