State the null and alternative hypotheses that would be used to test the followi
ID: 3154719 • Letter: S
Question
State the null and alternative hypotheses that would be used to test the following claims.
(a) There is a difference between the mean age of employees at two different large companies.
(b) The mean of population 1 is greater than the mean of population 2.
(c) The mean yield per county of sunflower seeds in North Dakota is less than the mean yield per county in South Dakota.
(d) There is no difference in the mean number of hours spent studying per week between male and female college students.
2. Is the national crime rate really going down? Some sociologists say yes! They say that the reason for the decline in crime rates in the 1980s and 1990s is demographics. It seems that the population is aging, and older people commit fewer crimes. According to the FBI and the Justice Department, 70% of all arrests are of males aged 15 to 34 years. (Source: True Odds, by J. Walsh, Merritt Publishing.) Suppose you are a sociologist in Rock Springs, Wyoming, and a random sample of police files showed that of 37arrests last month, 22 were of males aged 15 to 34 years. Use a 10% level of significance to test the claim that the population proportion of such arrests in Rock Springs is different from 70%.
Ho: p =0 .7; H1: p < 0.7; left-tailedHo: p 0.7; H1: p = 0.7; two-tailed Ho: p = 0.7; H1: p 0.7; two-tailedHo: p = 0.7; H1: p > 0.7; right-tailed
The t distribution, since the sample size is large.The normal distribution, since sample size is large.
At the = 0.10 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.At the = 0.10 level, we reject the null hypothesis and conclude the data are not statistically significant. At the = 0.10 level, we reject the null hypothesis and conclude the data are statistically significant.At the = 0.10 level, we fail to reject the null hypothesis and conclude the data are statistically significant.
Fail to reject the null hypothesis, there is insufficient evidence that the true proportion of arrests of males aged 14 to 34 in Rock Springs is different from 0.7.Fail to reject the null hypothesis, there is sufficient evidence that the true proportion of arrests of males aged 14 to 34 in Rock Springs is different from 0.7. Reject the null hypothesis, there is insufficient evidence that the true proportion of arrests of males aged 14 to 34 in Rock Springs is different from 0.7.Reject the null hypothesis, there is sufficient evidence that the true proportion of arrests of males aged 14 to 34 in Rock Springs is different from 0.7.
H0: 1 2 ---Select--- < = () = > = () 0 Ha: 1 2 ---Select--- = > = () = () < 0Explanation / Answer
a) H0: mu1-mu2=0
H1:mu1-mu2 not equal to 0.
b) H0: mu1-mu2=0
H1:mu1-mu2>0
c) H0:muN-muS=0
H1:muN-muS<0
d) H0:muM-muF=0
H1:muM-muF not equal to 0.
2. Step1. 0.1
Step2. H0:p=0.7, H1:p not equal to 0.7
Step3. Normal distribution, since sample size is large.
Step4. Z=(Ps-Pu)/sqrt [Pu(1-Pu)/N], where Ps is sample proportion, Pu is population proportion, N is sampl esize
=(22/37-0.7)/sqrt [0.7(1-0.7)/37]
=-1.40
Step5. p value is 0.1615
Step6. Option 3 distribution pictute.
Step7. At alpha=0.1, reject null hypothesis to conclude that data are statistically significant.
Step8. Last Option
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