In a survey of 1,000 television viewers, 40% said they watch network news progra

Question

In a survey of 1,000 television viewers, 40% said they watch network news programs. For a 90% confidence level, the margin of error for this estimate is 2.5%. If we want to be 92.5% confident, how will the margin of error change?

Since more confidence requires a more narrow interval, the margin of error will be smaller.

Since more confidence requires a more narrow interval, the margin of error will be larger.

Since more confidence requires a wider interval, the margin of error will be larger.

The margin of error will remain the same.

Since more confidence requires a wider interval, the margin of error will be smaller.

Since more confidence requires a more narrow interval, the margin of error will be smaller.

Since more confidence requires a more narrow interval, the margin of error will be larger.

Since more confidence requires a wider interval, the margin of error will be larger.

The margin of error will remain the same.

Since more confidence requires a wider interval, the margin of error will be smaller.

Explanation / Answer

In a survey of 1,000 television viewers, 40% said they watch network news programs. For a 90% confidence level, the margin of error for this estimate is 2.5%. If we want to be 92.5% confident, how will the margin of error change?

Since more confidence requires a more narrow interval, the margin of error will be larger.

that is because 92.5 has more accuracy , that means that the margin of error will be larger to select better the interval in where the proportion of population can be in the interval

Since more confidence requires a more narrow interval, the margin of error will be larger.

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