Assume you need to build a confidence interval for a population mean within some
ID: 3155602 • Letter: A
Question
Assume you need to build a confidence interval for a population mean within some given situation. Naturally, you must determine whether you should use either the t-distribution or the z-distribution or possibly even neither based upon the information known/collected in the situation. Thus, based upon the information provided for each situation below, determine which (t-, z- or neither) distribution is appropriate. Then if you can use either a t- or z- distribution, give the associated critical value (critical t- or z- score) from that distribution to reach the given confidence level.
a. 95% confidence n=150 known population data believed to be very skewed Appropriate distribution: Associated critical value: b. 99% confidence n=19 unknown population data believed to be normally distributed Appropriate distribution: Associated critical value: c. 95% confidence n=60 unknown population data believed to be skewed Appropriate distribution: Associated critical value: d. 99% confidence n=12 unknown population data believed to be very skewed Appropriate distribution: Associated critical value:Explanation / Answer
a)
As sigma is known, and n = 150 is large enough, we use Z DISTRIBUTION. [ANSWER]
Hence,
alpha/2 = (1 - confidence level)/2 = 0.025
Thus, by table/tchnology,
z(alpha/2) = 1.959963985 [ANSWER, CRITICAL VALUE]
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b)
As sigma is unknown, and the sample size is small (n = 19), but the population is normal, then we use T DISTRIBUTION. [ANSWER]
Hence,
df = n - 1 = 18,
alpha/2 = (1 - confidence level)/2 = 0.005
By table/technology,
t(alpha/2) = 2.878440473 [ANSWER, CRITICAL VALUE]
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c)
It depends on your convention in class, but usually, as n = 60, this is large enough, so we can use Z DISTRIBUTION. [ANSWER]
[Please still use the convention you use in class, if it is different.]
Hence,
alpha/2 = (1 - confidence level)/2 = 0.025
Thus, by table/tchnology,
z(alpha/2) = 1.959963985 [ANSWER, CRITICAL VALUE]
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d)
sigma is unknown, and n = 12 is small. We cannot use either distribution. [ANSWER, NEITHER]
[We cannot use either because the central limit theorem cannot be applied yet, as sigma is small and n = 12 is small.]
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