the number of successess and the sample size are given for a simple random sampl
ID: 3156103 • Letter: T
Question
the number of successess and the sample size are given for a simple random sample from a population. use the one proportion z interval procedure to find the required confidence interval X=16, n=40, 99% level the number of successess and the sample size are given for a simple random sample from a population. use the one proportion z interval procedure to find the required confidence interval X=16, n=40, 99% level the number of successess and the sample size are given for a simple random sample from a population. use the one proportion z interval procedure to find the required confidence interval X=16, n=40, 99% levelExplanation / Answer
Confidence Interval For Proportion
CI = p ± Z a/2 Sqrt(p*(1-p)/n)))
x = Mean
n = Sample Size
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=16
Sample Size(n)=40
Sample proportion = x/n =0.4
Confidence Interval = [ 0.4 ±Z a/2 ( Sqrt ( 0.4*0.6) /40)]
= [ 0.4 - 2.576* Sqrt(0.006) , 0.4 + 2.58* Sqrt(0.006) ]
= [ 0.2,0.6]
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