Five males with a particular genetic disorder have one child each. The random va
ID: 3156433 • Letter: F
Question
Five males with a particular genetic disorder have one child each. The random variable x is the number of children among the five who inherit the genetic disorder. Determine whether the table describes a probability distribution. If it does, find the mean and standard deviation.
x
0
1
2
3
4
5
P(x)
0.2373
0.3955
0.2637
0.0879
0.0146
0.0010
Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. = _
(Round to one decimal place as needed.)
B. The table is not a probability distribution.
Find the standard deviation of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. =_
(Round to one decimal place as needed.)
B. The table is not a probability distribution.
x
0
1
2
3
4
5
P(x)
0.2373
0.3955
0.2637
0.0879
0.0146
0.0010
Explanation / Answer
A) AS THE SUM OF PROBABILITIES GIVEN ABOVE I = 1 THEREFORE IT IS A PROBABILITY DISTRIBUTION
MEAN = E(X) = X1*P(X1)+X2*P(X2)+.....+XN*P(XN)
THEREFORE MEAN = 0*0.2372+1*0.3955+2*0.2637+3*0.0879+4*0.0146+5*0.001 = 1.25
B) VAR(X) = E(X^2)-E(X)^2
= 0*0.2372+1^2*0.3955+2^2*0.2637+3^2*0.0879+4^2*0.0146+5^2*0.001 - 1.25^2
= 2.5 - 1.56 = 0.94
STANDARD DEVIATION = SQRT(VARIANCE) = SQRT(0.94) = 0.969
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