A teacher wants to estimate the mean time (in minutes) students take to go from

Question

A teacher wants to estimate the mean time (in minutes) students take to go from one classroom to the next. His research assistant uses the sample time of 42 students to report the confidence interval as [7.40, 8.60]. Use Table 2.

a. Find the sample mean time used to compute the confidence interval. (Round intermediate calculations to 4 decimal places, "sample mean" to 2 decimal places.)

b. Determine the confidence level if the sample standard deviation used for the interval is 1.606. (Round intermediate calculations to 4 decimal places, "t" value to 3 decimal places, and final answer to the nearest whole number.)

Explanation / Answer

7.40 = mean - error

8.60 = mean + error

mean = 8

error = 0.6

b)

error= 0.6 = Z * 1.606 / srqt 42

Z = 2.42

alpha / 2 = 0.00776

alpha = 0.01552

confidence interval = 1 - 0.01552 = 0.98448 = 98%

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