Two researchers conducted a study in which two groups of students were asked to

Question

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 21.4 with a standard deviation of 3.5 while the 200 students in group 2 had a mean score of 18.5 with a standard deviation of 3.7 Determine the 90% confidence interval for the difference in scores, (__, __) (Round the variables to three decimal places as needed.)

Explanation / Answer

Determine the 90% confidence interval for the difference in scores

alpha / 2 = 0.05 Z= 1.64

I: 21.4 - 18.5 +/- 1.64 * SRQT [ (3.5^2 + 3.7^2)/ 200 ]

2.9 +/- 0.591

2.309 < miu1 - miu2 < 3.491

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