THERMODYNAMICS A cylinder is filled with water. Water mass is constant (Closed c
ID: 3160712 • Letter: T
Question
THERMODYNAMICS
A cylinder is filled with water.
Water mass is constant (Closed cylinder) = 2 kg
Cylinder diameter = 50 mm
Load mass = 20 kg
Atmospheric pressure = 1 bar
Opwarming af væsken = Heating the liquid
Fordampning = Evaporation
Overhedning af dampen = Heating of vapor
Heat is applied from state 1 to 4.
Determine the missing data using the following
State 1: Water with a temperature of 10 *C
State 2: Water at boiling point, start / initial
State 3: Water at boiling point, end
State 4: Water with a temperature of 200 *C
Hint 1: Pressure Ptotal should be calculated in order to use the tables
Hint 2: Reference specific entropy s(T=0*C)=0 and reference specific enthalpy h(T=0*C)=0.
Hint 3: Use Cp(water)= 4.20 kJ/(kg K) for states 1 and 2
p konstant tExplanation / Answer
Given mass =2kg
For State 1;
when temperature is 10*C
volume =0.002 m3
volume in liters=2
specific volume =volume /mass=0.002/2=0.001
specific entropy =0.15104805629986 kJ / kg K defined as ratio of energy to mass and temperature
specific enthalpy=42.42947857467 kJ / kg
vapour content=0 since only liguid state is present
for state 2
the temperature =100*C
volume=2 liters
specific volume remains the same as well as the density
specific entropy=1.3067647849535kJ / kg K
specific enthalpy =419.33843832629 kJ / kg
vapour content =0
for state 3
temperature is greater than 100*C means start of vapours
volume of liquidts decreasing while vapour volume starts increasingowing phase star decreasing and since the pressure is decreased due to movement ofload mass
v=1/2 of intial volume =0.001 an 1 litre respectively density =2000
specific entropy =7.3540770509584 kJ / kg K for vapour
specific enthalpy=2675.5720292208 kJ / kg for vapour
vapour content =50%
for state 4
volume =0 and also specific volume =0
density=2000
specific entropy=6.4302967720321 kJ / kg K for vapour only
specific enthalpy=2792.0615640123 kJ / kg for vapour only
vapour content =100%
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