At the start of take-off, the propeller on the 2.0-Mg plane exerts a horizontal

Question

At the start of take-off, the propeller on the 2.0-Mg plane exerts a horizontal thrust of 600 N on the plane (Figure 1) . Neglect the lifting force of the wings since the plane is originally at rest. The mass center is at G. W=2*10^3*9.81

Part A

Determine the plane's acceleration.

Express your answer to three significant figures and include the appropriate units.

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Part B

Determine the vertical reaction at the nose wheel A.

Express your answer to three significant figures and include the appropriate units.

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Part C

Determine the vertical reaction at each of the two wing wheels B.

Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

a)

Net force along the horizontal : Fnet = 600 N

So, acceleration , a = 600/(2*10^3) = 0.3 m/s2

b)

Let the normal force at A be Fa and at B be Fb

Equating torques about the center of mass :

Fa*1.6 - Fb*0.6 = 0

So, Fb = 8/3 *Fa

Now, Fa + Fb = W = 2*10^3*9.81 = 19620 N

So, Fa + 8/3*Fa = 19620 N

So, Fa = 5351 N and Fb = 14269 N

So, vertical reaction at A = 5351 N

c)

Vertical reaction at each of its wing wheels = 14269/2 = 7134.5 N

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