Cathode ray tube televisions work by accelerating electrons through a \"cathode

Question

Cathode ray tube televisions work by accelerating electrons through a "cathode ray tube" (a very simple particle accelerator), and directing them towards a screen. The screen is covered with particles that emit light in response to being struck by the electrons. The electrons are at rest before being accelerated through the tube. There exists a potential difference of-2.00 middot 10^4 V at the "starting" side of a television's cathode ray tube with respect to the screen. Over the course of an hour q = -0.0360 C of charge is accelerated through the tube. How much work is done by the tube on the charge over the course of one hour? In Saskatoon, electricity costs about 4.19 middot 10^-8 cents per Joule. How much does it cost to perform that work? (Note, because of energy losses due to heat it actually costs about 1.5 cents to run a television for an hour) 19.3 mu C of charge is transferred to a previously neutral spherical conductor of radius 6.0 cm. What is the electric potential at a point

Explanation / Answer

a)

Work done

W=qdV=(-0.036)*(-2*104)

W=720 J

b)

Cost =720*4.19*10-8=3.02*10-5 cents

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