In a right angle traingle ABC, angle ABC is 90 Degree, AB = 2 m, and angle ACB i

Question

In a right angle traingle ABC, angle ABC is 90 Degree, AB = 2 m, and angle ACB is 41.81 Degree. A point charge of 5* 42 nC is placed at point C, point charge 4* 42 nC is placed at point A and point charge 1 C is placed in point B. Calculate the force on charge at B due to others two. In a right angle traingle ABC, angle ABC is 90 Degree, AB = 2 m, and angle ACB is 41.81 Degree. A point charge of 5* 42 nC is placed at point C, point charge 4* 42 nC is placed at point A and point charge 1 C is placed in point B. Calculate the force on charge at B due to others two.

Explanation / Answer

here,

ACB = 41.81 degree

AB = 2 m

BC/AB = cot(ACB)

BC = 2 * cot(41.81) = 1.49 m

qC = 5 * 42 * 10^-9 C

qA = 4 * 42 * 10^-9 C

electric feild at B due to charge on A , Ea = k * qA /AB^2

Ea = 9 * 10^9 * 4 * 42 * 10^-9 /2^2

Ea = 378 N/C

electric feild at B due to charge on C , Ec = k * qA /AB^2

Ec = 9 * 10^9 * 5 * 42 * 10^-9 /2^2

Ec = 472.5 N/C

the electric feild at point B , E = sqrt(Ea^2 + Ec^2)

E = 605.1 N/C

as unit charge is placed at B

the electric force at point B is 605.1 N/C

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