S Solution Mx The rotor e x XG Modberm1 x y D CH13 pdf x e dynamics c x C Engine

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S Solution Mx The rotor e x XG Modberm1 x y D CH13 pdf x e dynamics c x C Engineerin x Master mngcomputerscience: Hwa 2 Ch13 proteemm elgse ohrome secure I https//sessi ID 5609251 signed in as Ahmed Arain 13.24 4 of 9 roblem 13.24 Part A What is the position of the object at t 6 s? The velocity of an object is v 200-20 m/s. Express your answer with the appropriate units. When t m 3 s, the position of the object is mo- 3983 lm a Submit My Answers om Incorrect; Try Again: 4 attempts remaining Part B What is the acceleration of the object at t Express your answer with the appropriate units. Value

Explanation / Answer

Here,

v = 200 - 2 * t^2

part A) for the position

change in position = integration(v .dt) from 3 s to 6 s

x - 300 = integration((200 - 2 * t^2)) .dt) from 3 s to 6 s

x - 300 = (200 * t - 2t^3/3) from 3 s to 6 s

x - 300 = (200 * 6 - 2 * 6^3/3) - (200 * 3 - 2* 3^3/3)

solving for x

x = 774 m

the position of the objecty at t = 6 s is 774 m

part b)

let the acceleration of the object is a

a = dv/dt

a = d/dt(200 - 2 * t^2 )

a = -4 * t

a = -4 * 6 = -24 m/s^2

the acceleration of the object at t = 6 s is -24 m/s^2

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