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View History Bookmarks People Window Help https://edugen willeyplus.com/edugen/student/mainfruni FULL SCREEN PRINTER VERttON Chapter 22, Problem os3 plate are cm apart and have a uniform of E-3.7s Nyc them (see the figure). An is released from the negative each at the same time that a proton is released from the positive plate. Neg the force of the partides on each other and find their dstance from the postive plate when they pass other, Plate -p--- Negative plate Number the tolerance is +/-1 in the 3rd signincant digit Click if you would like to work for this questiona open show work show Question Attempts: 0 of 3 used SAvr roR LArna MAMITANswER All Rights Reserved.

Explanation / Answer

Here ,

electric field , E = 3.75 N/C

a1 = e * E/me

a1 = 1.602 *10^-19 * 3.75/9.11 *10^-31

a1 = 6.59 *10^11 m/s^2

for the proton

acceleration is a2

Using second law of motion

a2 = 1.602 *10^-19 * 3.75/1.67 *10^-27

a2 = 3.59 *10^8 m/s^2

Now , let the time taken by them to pass is t

0.5 * a1 * t^2 + 0.5 * a2 * t^2 = 0.0776

0.5 * 6.59 *10^11 * t^2 + 0.5 *3.59 *10^8 * t^2 = 0.0776

solving for t

t = 4.85 * 10^-7 s

Now , distance of passing from positive plate = distance travelled by proton in this time

distance of passing from positive plate = 0.5 *3.59 *10^8 * (4.85 * 10^-7)^2

distance of passing from positive plate = 4.22 *10^-5 m

the distance of passing from positive plate is 4.22 *10^-5 m

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