Kinematics 1. A car accelerated from 4.1 mph to some final velocity over 9.6 s.
ID: 3162264 • Letter: K
Question
Kinematics
1. A car accelerated from 4.1 mph to some final velocity over 9.6 s. Then, going at this final velocity, the car traveled 4.1 miles over the course of the next 1.0 minutes.
What was acceleration of the car over the first 9.6 s?
2. Animal "one" accelerates from rest to 13.9 mph in 19.3 s. Animal "two" accelerates from rest to 3.8 mph in the same amount of time.
By what factor is the average acceleration developed by animal "one" greater than the average acceleration developed by animal "two"?
3. Animal "one" accelerates from rest to 18.3 mph over a distance of 15.6 meters. Animal "two" accelerates from rest to 7.3 mph within the same distance.
By what factor is the average acceleration developed by animal "one" greater than the average acceleration developed by animal "two"?
Explanation / Answer
1)
initial speed , u = 4.1 mph
u = 4.1 * 1609/3600 = 1.83 m/s
for the final velocity v
v = distance/time
v = 4.1 * 1609/(1 * 60)
v = 109.9 m/s
let the acceleration is a
a = (v-u)/t
a = (109.9 - 1.83)/9
a = 12.01 m/s^2
the acceleration of the car is 12.01 m/s^2
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