A capacitor consists of two large metal disk placed a distance s apart (see the

Question

A capacitor consists of two large metal disk placed a distance s apart (see the figure) The radius R of each disk is 5 am the gap's between the disks is 1.5.3 mm and the thickness I of each disk is 0.3 mm. The disk on the left has a net charge of 3.3 times 10^-4 C and the disk on the right has a net charge of -3.3 times 10^4 C Calculate the potential V_2. V_1, where location 1 is inside the left disk at its center and location 2 is the center of the air gap between the disk Use is =8.85 times 10^12 C^2/N middot m^2)

Explanation / Answer

E = q / pi r2 e0 = (3.3 * 10-4) / (pi * 5.82 * 8.85 * 10-12)

= 3.52 * 105 N/C

V1 = E * d = 3.52 * 105 * (0.3 mm / 2 ) = 52.8 V

V2 = E * d = 3.52 * 105 * (0.3 mm / 2 + 1.3 mm / 2) = 282 V

Potential difference = 282 - 52.8 = 229 V

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