You are a Pulmonary Bioengineer interested in developing better sensor transduce

Question

You are a Pulmonary Bioengineer interested in developing better sensor transducers to measure breathing. You want to understand the electrical characteristics of an elastic resistive transducer that is wrapped around the chest.

Assumptions and starting points:

Length of the transducer band = L

Starting Li = 35 cm

Resting, initial resistance of the transducer Ri = 0.9 k

The cross sectional area of the band, A, remains constant during stretching

Total resistance of the transducer = R = Ri x (L/Li)

Problems

1) The transducer is stretched around the chest, where L = 92 cm. What is the new resistance?

2) A constant current of 5 mA flows through the transducer wrapped around the chest, prior to breathing. Using Ohms Law, V = I x R, calculate the resting voltage that is induced across the chest transducer in Problem 1:

3) Normal breathing induces a 20% increase in chest circumference, and still a constant current of 5 mA flows through the transducer during breathing. What is the change in voltage due to the breath?

4) We are now interested in currents generated by placing metal electrodes in an electrolytic (e.g., ionizable) solution:

Half-cell potential of a zinc (Zn) electrode: -0.65

Half-cell potential of a copper (Cu) electrode: +0.39

4a) What is the potential drop between these 2 electrodes when placed in an electrolytic solution?

4b) Again using Ohm’s Law, assuming the resistance of the electrolytic solution is 2.5 k, what is the current between the Zn and Cu electrodes?

Explanation / Answer

the value of ne resistance is R = Ri x (L/Li)=0.9x(92/35)=2.36

V=IR=2.36*5=11.8 mV

i have answered according to guidelines

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