Hello guys! So I am doing a physics lab and am a little bit stuck on the post la

Question

Hello guys!

So I am doing a physics lab and am a little bit stuck on the post lab questions. To summarize the lab and what it is about:

Highly recommend you guys just do the questions part, but I still uploaded the procedure just in case to give you an idea of what the question are asking. Again if there are any questions that you feel you cannot answer unless you do the lab in real life then I encourage you to skip them, high rating correct answers!

Also please do not write in cursive because I cannot read it thanks!

Lab 5: Basic Circuits Contents: I. Introduction ll. Lighting an LED Ill. Series and Parallel IV. Kirchoff's Laws I. Introduction Purpose In this lab you will learn how to set up and measure some basic circuits in both series and parallel using a digital multimeter. You will also test out Kirchoff's Laws experimentally. Equipment Circuit scribe kit Digital multimeter with probe cables More about Cutaway view of a carbon resistor showing Resistors (carbon) Instead of using bulbs in this lab, you will the cross sectional use carbon resistors. A typical carbon area of the graphite resistor contains a form of carbon, known material as graphite, suspended in a hard glue binder. It usually is surrounded by a plastic case with a color code painted on it. The graphite material provides a relatively large resistance to the flow of electric current. Color 1st band 2nd band 3rd band Reading resistor color codes The color codes on the side of the carbon Black resistors tell what the resistance of the Brown 1 101 resistor is Red 2 L 2 102 The first two bands are the first two digits of the resistor's value, and the third band tells Orange 3 you how many zeroes to add. The fourth band tells you how accurate the resistance is Yellow 4 For example, if a resistor's bands are red, Green S S 105 yellow, orange, and gold, it would have a resistance of 24,000 Q. The gold band indicates that the resistance is good to t5%. Violet 7 7 107 Gray 8 8 108 White 9 9 109

Explanation / Answer

Answer1 :

Measure Volate across R1 , measure voltageacross R2 , the total of these two should equal the Voltage supply.

If we make a complete loop starting from the negative ground termial, the sum of all voltage changes we encounter will be equal to the Voltage of the voltage source because of the Kirchoff's loop rule which says that around a complete loop sum of voltage changes should be zero.

Answer 2: let volate across R1 be V1 so I1=V1/R1 , let voltage across R2 beV2 so I2=V2/R2

To satisy Kirchoffs junction rule , current passing through both resistors has to beequal. I1=I2 , show from your readings,

a little error may be due to measuremeent by voltmeter which uses a very small percetntage of current when measuring but usually its too small.

Answer 1 for part 3:

As we know around a complete loop voltage changes shouuld be zero, going clockwise we know potential decrease across a resistor so acroos R1 we have potential -V1+V1 (due to vattery source) =0

Across voltage source and R2 -V1+V1=0

Across R1 and R2, since we are going clockwise across R1 we have -V1 , whereas acroos R2 we have +V1

so total -V1+V1=0

Results should be consistent , there may be small error due to resistance of connecting wores in the circuit , voltmeter measurements, battery source etc.

Answer2: I n this case R1 and R2 are in parallel voltage acroos both is V1,

so current acroos R1 is I1=V1/R1 and current across R2 is I2=V2/R2

Therefre total flowing into junction is I1++I2 , total flowing out of junction is I1 in R1 and I2 in R2,

Confirm from measurements.

This should satisfy Kirchoffs Junction rules but very small error may again be due to resistance of connecting wores in the circuit , multimeter measurements, battery source etc.

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