Use Kirchhoff\'s rules to complete the equation for the upper loop. (Use any var

Question

Use Kirchhoff's rules to complete the equation for the upper loop. (Use any variable or symbol stated above as necessary. AN current is given in amperes. Do not enter any units.) 30 V = Use Kirchhoff's rules to complete the equation for the lower loop (Use any variable or symbol stated above as necessary. All currents are given in amperes. Do not enter any units.) - 24 V = Use Kirchhoff's rules to obtain an equation for the Junction on the left side (Use any variable or symbol stated above as necessary. All currents are given in amperes.) Solve the Junction equation for I_3 I_3 = Using the equation found in part (d), eliminate I_3 from the equation found in part (b). (Use any variable or symbol stated above as necessary. All currents are given in amperes. Do not enter any units.) 24 V = Solve the equations found in part (a) and part (e) simultaneously for the two unknowns for I_1 and I_2, respectively. I_1 = A I_2 = A Substitute the answers found in part (f) into the Junction equation found in part (d), solving for I_3. I_3 = A

Explanation / Answer

here,

a)

using KVL in the upprer loop

(5 + 8) * I1 + (11 + 7) * I2 = 18 + 12 = 30 V ...(1)

b)

using KVL lower loop

(11 + 7)*I2 - 5 * I3 = 12 - 36 = - 24 V ...(2)

c)

using KCL

I3 = I1 + I2 ...(3)

d)

from (1), (2) and (3)

i1 = 3.17 A

i2 = - 0.625 A

i3 = 2.55 A

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