The system in the figure consists of 5 point particles. Four identical point par

Question

The system in the figure consists of 5 point particles. Four identical point particles, each with mass m, are positioned at the corners of a square with sides d.The fifth point particle has a mass 2m and is located a distance 2d from the center of the square formed by the other four point particles, along a direction perpendicular to the square.

What is the distance (in cm) from the point particle with mass 2m to the center of mass of this system if d= 12 cm and m = 0.01 kg?

The system in the figure consists of 5 point particles. Four identical point particles, each with mass m, are positioned at the corners of a square with sides d.The fifth point particle has a mass 2m and is located a distance 2d from the center of the square formed by the other four point particles, along a direction perpendicular to the square.

What is the distance (in cm) from the point particle with mass 2m to the center of mass of this system if d= 12 cm and m = 0.01 kg?

Explanation / Answer

Here, for the centre of mass

distance of centre of mass from 2m = (m1 * x1 + m2 * x2)/(m1 + m2)

distance of centre of mass from 2m = (4m * 2d + 0 * 2m)/(6m)

distance of centre of mass from 2m = 8 *m * d/6m

distance of centre of mass from 2m = 4d/3

distance of centre of mass from 2m = 4 * 12/3

distance of centre of mass from 2m = 16 cm

the distance of centre of mass from 2m is 16 cm

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