The point changes in the figure below are located at the comers of an equilatera

Question

The point changes in the figure below are located at the comers of an equilateral triangle 25.0 cm on a side, where q_b = +14.0 mu C and q_c = 4.30 mu C (Assume that the x axis is directed to the fight.) a) Find the electric at the location of q_8 b) What is the force on q_s given that q_8 = +1.50 nC? Three spiders are resting on the vertices of a triangular web have a length of a = 0.78 m, as depicted in the figure. Two of the spiders (s_1 and s_2) have + 4.3 mu C charge while the other (S_2) has - 4.3 mu C charge. a) What are the magnitude and direction of the net force on the third spider (S_3)? b) Suppose the third spider (S_3) moves to the origin, would the not force on the third spider (S_3) be greaterthan, lessthan, or equalto the magnitude found in part (a)? greaterthan part (a) lessthan part (a) equal to part (a) c) What are the magnitude and direction of the net force on the third spider (S_3) when it is resting at the origin?

Explanation / Answer

Here ,

for the electric field due to qb

Eb = 9 *10^9 * 14 *10^-6/(0.25)^2

Eb = 2016000 N/C

for electric field due to qc

Ec = 9 *10^9 * 4.3 *10^-6/(0.25)^2

Ec = 619200 N/C

Now, for the net electric field

Enet = sqrt(2016000^2 + 619200^2 + 2 * 2016000 * 619200 * cos(120 degree))

Enet = 1.79 *10^6 N/C

the net electric field at the loaction of qa is 1.79 *10^6 N/C

for the direction

direction = 60 + arctan(2016000 * sin(120)/(2016000 * cos(120) + 619200))

direction = 162.55 degree

the angle of electric field is 162.55 degree

b) for the charge m qa = -1.50 nC

magnitude = 1.50 *10^-9 * 1.79 *10^6 N

magnitude = 2.69 *10^-3 N

direction = 180 + 162.55 = 342.55 degree

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