Q values for electron capture Number 13. I think i can do part A of the question
ID: 3163566 • Letter: Q
Question
Q values for electron capture
Number 13. I think i can do part A of the question on my own, so best answers will be awarded to whoever can get part B and C of the question! Thank you in advance! Explanations are appreciated extra too!
energy of the emitted neutrino and the energy Ul lllU Li nucleus kinetic 12. Defining Q value as (mi m c2, compute the range of neutrino energies the p d e v. Assume the in the solar fusion reaction p initial protons to have negligible kinetic energies 13. (a) For neutrino capuure actions v Ax e A X', show that the o value, defined as in the case of decays as Q mi mf)c2, is just [m (4x) m (4X)]c2 atomic masses. (b) Neglecting the small kinetic energy using given to the final nucleus (to conserve momentum), this Q value is equal to the minimum energy the neutrino must have to cause the reaction. Compute the minimum neutrino energy necessary for capture by Cl, by 71Ga, and by 115 (c) In the Davis experiment (Section 9.6), 37Cl is used to detect v from solar fusion 71 Ga and 115 In have also been proposed as solar neutrino detectors. Comment on the use of these detectors to observe neutrinos from the basic fusion reaction p p d et v (see Problem 12) and from the decay of 7Be (see Problem 11) Classify the following decays according to degree of forbiddenness: (a) 89Sr 89 Y (1) (b) 36 Cl (2 Arr (01)Explanation / Answer
b) Q= [m(37Cl) - m(37Ar) ] c2
= (35.453-39.948) amu. c2
= - 4.495 x 931MeV
= - 4185 MeV
For 71Ga
Q= (m71Ga) -(m71Ge) c2
= (69.723-72.64) amu C2
= - 2715 MeV
For 115In
Q= (m114In) - (m114Sn) c2
= (114.818 - 118.71) amu c2
= - 3623 MeV Note: 1 amu C2 = 931 MeV.
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