Given an electron ejected by the sun, how much force would it feel as it approac

Question

Given an electron ejected by the sun, how much force would it feel as it approached the Earth at the equator? Assume the electron's speed Given an electron ejected by the sun, how much force would it feel as it approached the Earth at the equator? Assume the electron's speed to be 90% the speed of light, approaches at the magnetic equator, and the Earth's magnetic field strength to be 20 mT when the electron encounters it. a) What initial direction would it travel (N, S, E, W)? b) How about if it approached at angle of 45 degrees? c) How much force would a photon receive? d) How big would the gyrations be when an electron encountered the Earth's magnetic field?

Explanation / Answer

a) From right hand rule, electron travels towards South

( F = q.(V*B) and keep your 4 fingers towards electron velocity path and round it towards earth's magnetic field B direction

F = q*v*B*sin()

b) South- East ( 45 degrees between S & E )

c) Same as electron as F is only charge dependent not mass dependent

=> F =1.6*10^-19*0.9*3*10^8*20*10^-3 =8.64*10^-13 N

d) r = m*V/(q*B) = 9.06*10^-31*0.9*3*10^9/(1.6*10^-19*20*10^-3) =0.76448 m

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